fixed PGP having to be selected twice

This commit is contained in:
Adithya Abraham Philip 2016-01-16 03:24:29 +05:30
parent f64018d0a2
commit a9a3ef0f67
1 changed files with 4 additions and 1 deletions

View File

@ -1270,9 +1270,12 @@ public class ConversationActivity extends XmppActivity
if (requestCode == REQUEST_DECRYPT_PGP) { if (requestCode == REQUEST_DECRYPT_PGP) {
mConversationFragment.onActivityResult(requestCode, resultCode, data); mConversationFragment.onActivityResult(requestCode, resultCode, data);
} else if (requestCode == REQUEST_CHOOSE_PGP_ID) { } else if (requestCode == REQUEST_CHOOSE_PGP_ID) {
// the user chose OpenPGP for encryption and selected his key in the PGP provider
if (xmppConnectionServiceBound) { if (xmppConnectionServiceBound) {
if (data.getExtras().containsKey(OpenPgpApi.EXTRA_SIGN_KEY_ID)) { if (data.getExtras().containsKey(OpenPgpApi.EXTRA_SIGN_KEY_ID)) {
// associate selected PGP keyId with the account
mSelectedConversation.getAccount().setPgpSignId(data.getExtras().getLong(OpenPgpApi.EXTRA_SIGN_KEY_ID)); mSelectedConversation.getAccount().setPgpSignId(data.getExtras().getLong(OpenPgpApi.EXTRA_SIGN_KEY_ID));
// we need to announce the key as described in XEP-027
announcePgp(mSelectedConversation.getAccount(), null); announcePgp(mSelectedConversation.getAccount(), null);
} else { } else {
choosePgpSignId(mSelectedConversation.getAccount()); choosePgpSignId(mSelectedConversation.getAccount());
@ -1283,7 +1286,7 @@ public class ConversationActivity extends XmppActivity
} }
} else if (requestCode == REQUEST_ANNOUNCE_PGP) { } else if (requestCode == REQUEST_ANNOUNCE_PGP) {
if (xmppConnectionServiceBound) { if (xmppConnectionServiceBound) {
announcePgp(mSelectedConversation.getAccount(), null); announcePgp(mSelectedConversation.getAccount(), mSelectedConversation);
this.mPostponedActivityResult = null; this.mPostponedActivityResult = null;
} else { } else {
this.mPostponedActivityResult = new Pair<>(requestCode, data); this.mPostponedActivityResult = new Pair<>(requestCode, data);