don't throw assertion error when building session with same device id from other contact
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@ -364,6 +364,10 @@ public class AxolotlService implements OnAdvancedStreamFeaturesLoaded {
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return axolotlStore.getLocalRegistrationId();
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}
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public AxolotlAddress getOwnAxolotlAddress() {
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return new AxolotlAddress(account.getJid().toBareJid().toPreppedString(),getOwnDeviceId());
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}
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public Set<Integer> getOwnDeviceIds() {
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return this.deviceIds.get(account.getJid().toBareJid());
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}
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@ -453,6 +457,7 @@ public class AxolotlService implements OnAdvancedStreamFeaturesLoaded {
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} else {
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Element item = mXmppConnectionService.getIqParser().getItem(packet);
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Set<Integer> deviceIds = mXmppConnectionService.getIqParser().deviceIds(item);
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Log.d(Config.LOGTAG,account.getJid().toBareJid()+": retrieved own device list: "+deviceIds);
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registerDevices(account.getJid().toBareJid(),deviceIds);
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}
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}
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@ -822,7 +827,7 @@ public class AxolotlService implements OnAdvancedStreamFeaturesLoaded {
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private void buildSessionFromPEP(final AxolotlAddress address) {
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Log.i(Config.LOGTAG, AxolotlService.getLogprefix(account) + "Building new session for " + address.toString());
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if (address.getDeviceId() == getOwnDeviceId()) {
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if (address.equals(getOwnAxolotlAddress())) {
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throw new AssertionError("We should NEVER build a session with ourselves. What happened here?!");
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}
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